(x+2)^3-(x-1)^3=x(3x+4)=8

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Solution for (x+2)^3-(x-1)^3=x(3x+4)=8 equation: 



(x+2)^3-(x-1)^3=x(3x+4)=8

We move all terms to the left:

(x+2)^3-(x-1)^3-(x(3x+4))=0



We calculate terms in parentheses: -(x(3x+4)), so:

x(3x+4)

We multiply parentheses

3x^2+4x

Back to the equation:

-(3x^2+4x)



We get rid of parentheses

-3x^2+(x+2)^3-(x-1)^3-4x=0

We add all the numbers together, and all the variables

-3x^2-4x+(x+2)^3-(x-1)^3=0

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